Calculus I

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Find the derivative

** (sq root)

y = (square root) x + (2nd sq root) x +
(3rd sq root) x

** All the x's is under three sq roots

y' = 1/2(sq rt) x + 1/(sq rt) x +
3/2(sq rt) x


Is this right?

  • Calculus I -

    Go on: wolframalpha dot com

    When page be open in rectangle type:


    derivative your expresion

    and click option =


    After few seconds when you see result click option:

    Show steps

    If square root) x + (2nd sq root) x +
    (3rd sq root) x

    mean

    sqrt(x )+2*sqrt(x)+3*sqrt(x)


    type:

    derivative sqrt(x )+ 2* sqrt(x)+3*sqrt(x)

    and click option =

    then

    Show steps


    On wolfram alpha dot com you can practice any kind ofCalculus

  • Calculus I -

    ok thank you

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