# Calculus I

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Find the derivative

** (sq root)

y = (square root) x + (2nd sq root) x +
(3rd sq root) x

** All the x's is under three sq roots

y' = 1/2(sq rt) x + 1/(sq rt) x +
3/2(sq rt) x

Is this right?

• Calculus I -

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derivative your expresion

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If square root) x + (2nd sq root) x +
(3rd sq root) x

mean

sqrt(x )+2*sqrt(x)+3*sqrt(x)

type:

derivative sqrt(x )+ 2* sqrt(x)+3*sqrt(x)

and click option =

then

Show steps

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• Calculus I -

ok thank you

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