Calculus I
posted by Priscilla .
Find the derivative
** (sq root)
y = (square root) x + (2nd sq root) x +
(3rd sq root) x
** All the x's is under three sq roots
y' = 1/2(sq rt) x + 1/(sq rt) x +
3/2(sq rt) x
Is this right?

Calculus I 
Bosnian
Go on: wolframalpha dot com
When page be open in rectangle type:
derivative your expresion
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If square root) x + (2nd sq root) x +
(3rd sq root) x
mean
sqrt(x )+2*sqrt(x)+3*sqrt(x)
type:
derivative sqrt(x )+ 2* sqrt(x)+3*sqrt(x)
and click option =
then
Show steps
On wolfram alpha dot com you can practice any kind ofCalculus 
Calculus I 
Priscilla
ok thank you
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