Discreate Math
posted by Carlton .
Suppose that a department contains 13 men and 19 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men

Define n choose r as (n,r)=n!/(r!(nr)!)
Number of ways to choose 2 men and 4 women
=(13,2)*(19,4)
Number of ways to choose 1 man and 5 women
=(13,1)*(19,5)
Number of ways to choose 0 man and 6 women
=(13,0)*(19,6)
Total=?