The solubility product expression for mercury(I) iodide, Hg2I2 is Ksp = ?

My answer is [Hg2^2+^][2I^-^]^2^

Would you agree?

Still not right.

[Hg2++][I-]2

That last one is ok.

close.

Hg2I2 ==> Hg2++ + 2I-

Ksp = [Hg2++]2[I-]2
I hope that turns out ok. It's always so easy to miss turning that on or off. The ++ is the same as 2+

Explain betterly

Hg2I2==>hg2^2+2I-.......coz Hg2^2 always exist in dimeric form

[hg2 ^2+] [I-]^2

See what I mean?

Ksp = [Hg2++]2[I-]2
Let's see if this looks ok.