Pre-Cal

posted by .

I'm trying to put this parabola in standard form which is: (y-k)^2=4p(x-h)

The equation is x=(1/12)(y-2)^2 +6

Here is what i have so far:

x=(1/12)(y-2)^2 +6
-6 -6
x-6=(1/12)(y-2)^2
*12 *12
Would it be
12x-6 OR 12x-72?

thanks

  • Pre-Cal -

    from
    x-6=(1/12)(y-2)^2
    multiply both sides by 12

    12(x-6) = (y-2)^2 , which of course is

    (y-2)^2 = 12(x-6) , leave it like that, or you lose the form requested.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra 2 -Conics

    The directions are : Write each equation in standard form (if needed), then find appropriate information for the particular conic. the question: y=2x^2-12x+19 HOW DO I BEGIN?
  2. pre cal

    write the standard form equation of the parabola with vertex (-2,-2) that goes through point (-1,0) y= a (x-b)^2 + c b has to be -2, that gives the shift to the left. y=a( x+2)^2 + c when x=-2, y=-2, that makes c -2 y=a( x+2)^2 -2 …
  3. pre cal

    find the standard form of the equation of a parabola with the vertex (0,0) and the directrix y=6 find the standard form of the equation of the ellipse with center (0,0) and foci at (+- 4square root 3, 0) and verticies (+-8,0)
  4. Algebra 2

    I have a question and I can not figure it out. Any answers to the following along with any explanation would be great! Here is the equation: x=.2y^2-2y-3 Now I know that is an equation for a parabola. Now, I need the following: Equation …
  5. Precalc

    How would I put this parabola in standard form: x^2-6x+8y-31 Here how I started it: x^2-6x+9=-8y+31 Im not sure what to do from here :(
  6. pre cal

    What is the center of the conic whose equation is x^2 + 2y^2 - 6x + 8y = 0 2.Which one of the following equations represents a hyperbola?
  7. Pecalculs

    Can anyone put this parabola into this standard form: x-h = a(y-k)^2 x^2-12x-48y-372=0 ?
  8. Parabola

    How do I put this parabola in standard form?
  9. pre cal

    finding the standard form the center eccentricity vertices foci and minor axis endpoints of the equation 12x^2+4y^2-24x-4y+1=0
  10. Algebra

    Can you please help me with the below question: The vertex of a parabola is located at (-12, -1). The parabola also passes through the point (-10, 5). Write the equation of this parabola in both vertex form and standard form. Vertex …

More Similar Questions