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What is the [H3O+] for a neutral solution at 50 degrees celsius?

I know that kw=[H3O+][OH-] but I am not sure what to do to get the H3O. The value I have for kw=5.76e-14 and I have the pH 6.62 but I do not know what the OH would be.

A neutral solution has H3O^+ = OH^- so if the pH = 6.62 then the pOH 6.62
pH = 6.62 = -log(H3O^+).
Solve for (H3O^+)

I don't know if I put this in my calculator correctly but I got -0.82 after taking the -log of 6.62.

• Chemistry(Please respond, thank you) -

Key in 6.62, change the sign to negative, then punch the 10x button. The screen should return 2.3988E-7 which rounds to 2.40E-7M = OH^- = H3O^+

• Chemistry(Please respond, thank you) -

Oh ok I got it now thank you.

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