posted by Lisa .
Using the concentration of CH3COOH (0.8326M) and the equilibrium concentration of H3O+ (OJ = 31.6x10^-6 and milk = 3.16x10^-8), complete the reaction table for vinegar. Then calculate the acidity constant. Please show all work in solving the problem.
CH3COOH(aq) + H2O(l) <---> CH3COO-(aq) + H3O+(aq)
You need to clarify the post. What's the H3O^+ in OJ and milk to do with Ka for CH3COOH?