PreCalc Helppp!!!
posted by John .
Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers so that B1 is smaller than B2.)
a = 39, c = 40, angle A = 36°
angle B1 = ° angle B2 = °
angle C1 = ° angle C2 = °
b1 = b2 =

sin 36/39 = sin C /40
C = sin^1(40/39)sin 36 = 37
B = 180  A C = 107
C could also be in Quadrant 2
180  37 = 143
then B is 180  36 143 = 1 deg
sinB/b = sin 36/39 = .0151
so
b = sin B/.0151
b1 = sin 1 /.0151 = 1.16
b2 = sin 107/.0151 = 63.3 
Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
a = 26, b = 32, c = 27
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