calculus
posted by robert .
find the total differential of the function
f(x,y)= xye^(x+y)

calculus 
Steve
df = ∂f/∂x dx + ∂f/∂y dy
f = xye^(x+y)
df = (ye^(x+y) + xye^(x+y)) dx + (xe^(x+y) + xye^(x+y)) dy
= e^(x+y) [ (x+1)y dx + (y+1)x dy]
or, separating the product a bit,
f = xe^x * ye^y
df = e^x(x+1)*ye^y dx + e^y(y+1)*xe^x dy
= e^x*e^y [(x+1)y dx + (y+1)x dy]
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