Post a New Question

alge

posted by .

The angle of elevation of the sun is 31 degrees. Find the length of the shadow, to the nearest foot, of a man that is 6 feet tall.

  • alge -

    length of shadow --- x ft

    tan31° = 6/x
    x = 6/tan31 = 9.98567... or appr 10 ft

  • alge -

    9.99

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Pre-calculus

    The angle of elevation from the end of the shadow to the top of the building is 63 degrees and the distance of 220 feet. 1) Find the height of the building to the nearest foot 2) find the length of the shadow to the nearest foot If …
  2. 12th grade

    Angle elevation of sun is 25 degrees. Find the length the shadow cast by a tree 41 feet tall.
  3. Math

    At a certain time, a verical pole 10 feet tall casts a 14-foot shadow. What is the angle of elevation of the sun to the nearest degree?
  4. Math

    At a certain time a verical pole 10 feet tall casts a 14-foot shadow. What is the angle of elevation of the sun to the nearest degree?
  5. trig

    a 7 foot tall man is standing 65 feet away from a tower. if the angle of elevation is 35 degrees. what is the height of the tower to nearest tenth of a foot?
  6. Algebra 2

    if the angle of elevation of the sun with the ground is 10 degrees, what is the length of a shadow cast by a six foot person to the nearest foot?
  7. Algebra

    In 1915, the tallest flagpole in the world was in San Francisco. a. When the angle of elevation of the sun was 55 degrees, the length of the shadow cast by this flagpole was 210 ft. Find the height of the flagpole to the nearest foot. …
  8. Math Urgent help please

    A lamppost casts a shadow of a man who is standing 15 feet away from the lamppost. The shadow is 5 feet long. The angle of elevation from the tip of the shadow to the lamp is 50. To the nearest foot, the lamppost is _____ feet tall. …
  9. math

    a building casts a 25 foot shadow on a sunny day. If the angle of elevation from the tip of the shadow to the top of the building is 65 degrees, what is the height of the building to the nearest tenth of a foot?
  10. Math

    1) A television tower is 160 feet high and an observer is 120 feet from the base of the tower. Find, to the nearest degree, the angle of elevation of the top of the tower from the point of observation. 2) A vertical pole 22 meters …

More Similar Questions

Post a New Question