Calculus

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derivative of y=ln2^x

please help, I am getting the wrong answer every time

  • Calculus -

    not sure what you have there

    ln(2^x)?
    ln(2^x) = x*ln2

    y' = ln2


    y = log2x ?
    y = lnx/ln2
    y' = 1/(x*ln2)

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