Chemistry
posted by PLEASE HELP ME!! .
We conducted an expirement to detect disulphide groups in protein. One tube(lysozyme) contained unkowns, had approx 9.34 micromoles of disulphide groups.
The question asks me to work backwards through all the dilution factors taken to give number of micromoles of disulphide groups per ml of original solution.
These are the steps taken to prepare the lysozyme tube:
 A tube of lysozyme solution of 1:32 dilution of lysozyme solution( 0.5mg/ml)
0.0001M of FMA in 0.01M NAOH (provided) should be diluted 1:10 with 1M NaOH.
Add 8ml of 1M NaOH
Please if you any further questions, let me know
thanks.
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college subject=chemistry
Q#2..96g of sulphur reacts with 36g of carbon according to the following equation and produces carbon disulphide 2S + C = CS2 (a) the mass of carbon disulphide (b) the excess amount of the reagent in grams that is left unreacted.