Questions LLC
Login
or
Sign Up
Ask a New Question
Physics
Optics
Lens System
A sharp image is located 83.0 mm behind a 62.0 mm focal-length converging lens.
Find the object distance by calculation.
1 answer
Di=DoF/Do-F Substitute values... Do=390 mm
You can
ask a new question
or
answer this question
.
Related Questions
Which of the following arrangements will create an image larger than the object?
a diverging lens with the object placed between
An object is placed at a distance of 60 cm from a converging lens with a focal length of 20cm. What is the magnification of the
Which of the following adjustments would cause an image to change from real to virtual?
a)moving the object from the focal point
the thin lens equation in physics is 1/s+1/S=1/f where s is the object distance from the lens,S is the image distance from the
A converging lens of focal length f1 = +22 .5cm is placed at a distance d = 60 .0cm to the left of a diverging lens of focal
Two converging lenses are separated by 23.40 cm. The focal length of each lens is 12.20 cm. An object is placed 35.00 cm to the
A 1.00-cm-high object is placed 3.10 cm to the left of a converging lens of focal length 8.30 cm. A diverging lens of focal
A converging lens has a focal length of 0.060 m. An object is located 0.020 m to the left of this lens. A second converging lens
A converging lens has a focal length of 0.060 m. An object is located 0.020 m to the left of this lens. A second converging lens
An object is placed 30mm in front of a lens. An image of the object is located 90mm behind the lens.
a) Is the lens converging or