algebra
posted by Anonymous .
$6300 is invested,part of it at 10% and part of it at 7%.For a certain year, the total yield is $534.00. How much was invested at each rate

amount invested at 10%  x
amount invested at 7%  6300x
solve for x ....
.1x + .07(6300x) = 534
I suggest multiplying each side by 100 
$6300 is invested, part of it at 10% and part of it at 69%. For a certain year the total yield is $598.00. How much invested at each rate?
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