algebra

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$6300 is invested,part of it at 10% and part of it at 7%.For a certain year, the total yield is $534.00. How much was invested at each rate

  • algebra -

    amount invested at 10% --- x
    amount invested at 7% --- 6300-x

    solve for x ....

    .1x + .07(6300-x) = 534

    I suggest multiplying each side by 100

  • algebra -

    $6300 is invested, part of it at 10% and part of it at 69%. For a certain year the total yield is $598.00. How much invested at each rate?

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