Respond to this Question
Similar Questions

Math
Verify the identity . (cscXcotX)^2=1cosX/1+cosX _______ sorry i cant help you (cscXcotX)=1/sinX  cosX/sinX = (1cosX)/sinX If you square this you have (1cosX)^2/(sinX)^2 Now use (sinX)^2 = 1  (cosX)^2 to get (1cosX)^2 / 1  … 
trig
express this in sinx (1/ cscx + cotx )+ (1/cscx cotx) i got 2sinx is that right? 
Trigonometry.
( tanx/1cotx )+ (cotx/1tanx)= (1+secxcscx) Good one! Generally these are done by changing everything to sines and cosines, unless you see some obvious identities. Also generally, it is best to start with the more complicated side … 
drwls
My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to … 
Math
verify that the equation is an identity: (1cosX)/(1+cosX) = (cscXcotX)^2 
Math
Im really struggling with these proving identities problems can somebody please show me how to do these? 
Math
Im really struggling with these proving identities problems can somebody please show me how to do these? 
trigonometry
can i use factoring to simplify this trig identity? 
Math
square root of (1cosx/1+cosx) = cscx  cotx prove the identity 
Precalculus/Trig
I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1  cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1cosx Simplified: cosx + sin^3x/sin^3x = cscx/1cosx I don't know …