Algebra
posted by Shannon .
Mark made a business trip of 290 miles. He averaged 56 mph for the first part of the trip and 60 mph for the second part. If the trip took 5 hours, how long did he travel at each rate?

time for first trip  x hrs
time for 2nd part of trip  (5x)
distance for 1st part = 56x miles
distance for 2nd part = 60(5x)
so solve:
56x + 60(x5) = 290
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