calculus
posted by angelia .
need help simplifying some trig identities such as:
(csc t) (sin t)
cos t = 0.75 and tan t = 0.88, find sec t and cot t;
(cot2t) (sin2t) + sin2 t;
csc2t  cot2t/sin2t

small discrepancy in your given information
if cos t = .75 = 75/100 = 3/4
then we have a triangle with x=3, y = ? and hypotenuse = 4
3^2 + y^2 = 4^2
y^2 = 7
y = √7
then tan t = √7/3 = .881917.. , not .88
so sec t = 4/3 and cot t = 3/√7
not clear on your typing for
(cot2t)(sin2t) + sin2 t
is that last part sin^2 t ??????