# precal

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cosx/sinxcotx=1

• precal -

LS = cotx cotx
= cot^2 x
≠ RS

This is not an identity the way you typed it

if you meant
cosx/(sinxcotx) = 1
LS = cosx/(sinxcosx/sinx)
= cosx/cosx
= 1
= RS

See how important it is to use brackets when typing in this way ?

• precal -

I apologize 4 the typo, that's how the work was given to me.

• precal -

But thanks alot!

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