Post a New Question


posted by .

The rate constant for this first-order reaction is 0.0570 s–1 at 400 °C.
After how many seconds will 14.0% of the reactant remain?

  • chemistry -

    ln(No/N) = kt
    If you use No = 100, then N = 14, substitute k and solve for t.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question