posted by Debbie .
Checking to see if I did this right?
Titration of HN03 titrated with NaOH
ending result is 1.38.
Titration A, endpoint pH = 8 is pKa or pKb= 1.38x106=5.861 and
Titration of NH03 titrated with KOH ending results 1.54.
Titration B, endpoint pH = 7 is KaorKb=
Chem 2 -
Beats me. I don't know what you're describing.