A 0.31 kg pendulum bob passes through the lowest part of its path at a speed of 2.02 m/s.
The acceleration of gravity is 9.8 m/s2 .
What is the tension in the pendulum cable at this point if the pendulum is 72 cm long?
Answer in units of N
Tension = M*[(V^2/L) + g)]
To find the tension in the pendulum cable at the lowest point, we can use the equation for centripetal force:
F = m * a
Where:
F is the force (tension in the pendulum cable)
m is the mass of the bob (0.31 kg)
a is the centripetal acceleration
The centripetal acceleration can be determined using the formula:
a = v^2 / r
Where:
v is the velocity of the bob at the lowest point (2.02 m/s)
r is the length of the pendulum (72 cm = 0.72 m)
Plugging in the values, we have:
a = (2.02 m/s)^2 / 0.72 m
a = 5.68 m^2/s^2
Now, we can substitute the values of mass (m) and acceleration (a) into the equation for force:
F = (0.31 kg) * (5.68 m^2/s^2)
F = 1.7576 N
Therefore, the tension in the pendulum cable at the lowest point is approximately 1.7576 N.