Calculus
posted by ASAP .
A cardboard box of 32in^3 volume with a square base and open top is to be constructed. What is the length of base that will minimize the surface area?

Volume=s^2*h=32
Surface area = s^2 + 4*s*h
using volume equation, h=32/s^2
SA= s^2 + 4*s*(32/s^2) = s^2 + 128/s
Take derivative dSA/ds and set equal to zero.
2s  128/s^2 = 0
s^3 = 64
s = 4
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