math
posted by Jordan .
Find the dimensions of a rectangle with perimeter 40 with the largest area. (hint: Find an equation for area and one for perimeter, use both to find perimeter in terms of one variable)

let the width be x
and the length be y
2x + 2y = 40 or
x+y=20 > y = 20x
Area = xy = x(20x
= 20x  x^2
Are you in Calculus?
Then the solution is very easy
If not in Calculus, complete the square of this quadratic, again a very basic problem.
Let me know what you get. 
sdfasdf
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