2.5 X 10^(-3) = (.28)(.38) / x^2
Solve for x.
2.5 X 10^(-3) = 0.1064 / x^2
2.5 X 10^(-3) X 0.1064 = 266
sqrt 266 = 16.3
Did I do this correctly?? Thank you for your help.
2.5 * 10 ^ ( - 3) = ( 0.28 ) * ( 0.38 ) / x ^ 2 Multiply both sides by x ^ 2
2.5 * 10 ^ ( - 3) * x ^ 2 = ( 0.28 ) * ( 0.38 )
2.5 * 10 ^ ( - 3) * x ^ 2 = 0.1064 Divide both sides by 2.5 * 10 ^ ( - 3)
x ^ 2 = 0.1064 / 2.5 * 10 ^ ( - 3)
x ^ 2 = 0.1064 * 10 ^ 3 / 2.5
Remark: 1 / 10 ^ ( - 3 ) = 10 ^ 3
x ^ 2 = 0.1064 * 1000 / 2.5
x ^ 2 = 106.4 / 2.5
x ^ 2 = 42.56
x = sqrt ( 42.56 )
x = ± 6.5238
thank you for your help
If you must simplify your answer:
x ^ 2 = 106.4 / 2.5 * ( 10 / 10 )
x ^ 2 = 1064 / 25
x ^ 2 = 4 * 266 / 25
x = sqrt ( 4 * 266 / 25 )
x = ± (2 / 5 ) * sqrt ( 266 )
To solve for x in the equation 2.5 x 10^(-3) = (.28)(.38) / x^2, you have correctly squared both sides of the equation to eliminate the x^2 term in the denominator. However, it seems that you have made an error in calculating the right-hand side of the equation.
To solve it correctly, let's step through the problem together:
Given equation: 2.5 x 10^(-3) = (.28)(.38) / x^2
Multiply both sides of the equation by x^2 to eliminate the denominator:
2.5 x 10^(-3) x x^2 = (.28)(.38)
Simplify the left side to get:
2.5 x 10^(-3+2) x = (.28)(.38)
Simplify the exponent:
2.5 x 10^(-1) x = (.28)(.38)
Multiply the decimals on the right-hand side:
2.5 x 10^(-1) x = 0.1064
Now, we need to solve for x. Divide both sides by 2.5 x 10^(-1):
x = 0.1064 / (2.5 x 10^(-1))
To simplify this fraction, divide 0.1064 by 2.5, then multiply by 10^1. Doing this, we get:
x = 0.04256 x 10 = 0.4256
Therefore, x is approximately 0.4256.
It seems that you made an error when multiplying 2.5 x 10^(-3) by 0.1064. The correct result is:
2.5 x 10^(-3) x 0.1064 = 0.000266
Then, taking the square root of 0.000266, we get approximately 0.0163, not 16.3 as you mentioned.
So, the final answer for x is approximately 0.0163, not 0.4256.
I hope this clears up any confusion and helps you understand the correct solution to the problem. Let me know if you have any further questions!