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FIND THE SLOP of line containing points(-2,8) and (3,5)

  • algebra -

    -3/5

  • algebra -

    Two point form of linear equation :

    y - y 1 = ( y 2 - y 1 ) * ( x - x 1 ) / ( x 2 - x 1 )

    Te slope is explicitly given as

    m = ( y 2 - y 1) / ( x 2 - x 1 )

    In this case :

    x 1 = - 2

    x 2 = 3

    y 1 = 8

    y 2 = 5

    m = ( y 2 - y 1 ) / ( x 2 - x 1 )

    m = ( 5 - 8 ) / [ 3 - ( - 2 ) ]

    m = - 3 / ( 3 + 2 )

    m = - 3 / 5 = - 0.6

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