AP CHEMISTRY

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Calculate the solubility of LaF3 in grams per liter in the following solutions. (Ksp = 2. 10-19.)
a) pure water
Ans: .00182g/L

b) 0.037 M KF solution

c) 0.055 M LaCl3 solution

NEED b&c
PLEASE HELP

  • AP CHEMISTRY -

    Let x = solubility LaF3.
    ...........LaF3 ==> La^3+ + 3F^-
    ............x.......x.......3x

    ...........KF ==> K^+ + F^-
    initial.0.037......0....0
    change...-0.037..0.037...0.037
    equil.....0.....0.037...0.037

    Ksp LaF3 = (La^3+)(F^-)^3
    From the above charts.
    (La^3+) = x
    (F^-) = 3x from the LaF3 and 0.037 from the KF to make a total of 3x+0.037
    Solve for x

    c is done the same way except
    (La^3+) = x from LaF3 + 0.0055 from LaCl3.
    (F^-) = 3x
    Solve for x.

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