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A 20.0 mL sample of an aqueous HClO3 solution is titrated with a 0.0275 M KOH solution. The equivalence point is reached with 28.5 mL of the base. The pH of the HClO3 solution, before titration, is

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    From the titration data you determine the M HClO3.
    mL HClO3 x M HClO3 = mL NaOH x M NaOH.

    Then given the HClO3 concn,
    (H^+) = (HClO3) and
    pH = -log(H+)

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