chemistry

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Ca(OH)^2 does not completely dissociate. It only partially dissotiates in water to form OH- and Ca+2. An equilibrium mixture of Ca(OH) and its dissolved ions is found to have a pH= 10.3 what is Kc for this dissociation?

  • chemistry -

    pH = 10.3.
    pH + pOH = pKw = 14; therefore, pOH = 3.7 and pOH = -log(OH^-).
    (OH^-) = 2E-4

    ............Ca(OH)2 ==> Ca^2+ + 2OH^-
    ................x.........x........2x
    Kc = (Ca^2+)(OH^-)^2
    (Ca^2+) = 1/2(2E-4)
    (OH^-) = 2E-4
    Solve for Kc.

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