a series RLC circuit has a peak current of 4 A with a frequency of 23 kHz. if the resistance of the circuit is 60 kohm, the capacitance of the circuit is 16 uF, and the unductance of the circuit is 24 uH, determine the average power of the circuit.

I = 0.707*4 = 2.828A rms.

P = I^2*R = (2.828)^2 * 60 = 480 kW.

To determine the average power of the circuit, we need to calculate the voltage across the circuit components and use them to find the average power using the formula:

Average Power = (Voltage across the resistor * Voltage across the inductor * Voltage across the capacitor) / (Total resistance)

Let's calculate the voltage across each component first:

1. Voltage across the resistor (Vr) can be calculated using Ohm's Law: Vr = I * R, where I is the peak current and R is the resistance. Plugging in the values, we get Vr = 4 A * 60 kohm.

2. Voltage across the inductor (Vl) can be calculated using the formula Vl = I * XL, where I is the peak current and XL is the inductive reactance. The inductive reactance can be calculated using the formula XL = 2 * pi * f * L, where f is the frequency and L is the inductance. Plugging in the values, we get XL = 2 * pi * 23 kHz * 24 uH and then Vl = 4 A * XL.

3. Voltage across the capacitor (Vc) can be calculated using the formula Vc = I * XC, where I is the peak current and XC is the capacitive reactance. The capacitive reactance can be calculated using the formula XC = 1 / (2 * pi * f * C), where f is the frequency and C is the capacitance. Plugging in the values, we get XC = 1 / (2 * pi * 23 kHz * 16 uF) and then Vc = 4 A * XC.

Now that we have calculated the voltage across each component, we can find the average power:

Average Power = (Vr * Vl * Vc) / (Total resistance)

Let's plug in the values and calculate the average power.