posted by Mo .
The region bounded by y= 1/(x^2+2x+5), y=0, x=0, and x=1, is revolved about the x-axis. Find the volume of the resulting solid.
Calc 2 -
= π∫1/(x^2 + 2x + 5)^2 dx from 0 to 1
messy integration, I don't know how to do it,