Calc
posted by Elli .
f(x)=x^33x^23x8/(3x^24x6)
Find the equation of the nonvertical asymptote.
What is the smallest value of x at which f(x) intersects its nonvertical asymptote?

since for large x, f(x) just looks like x^3/3x^2, the asymptote is y = x/3
So, how to find there the curve intersects the asymptote? Duh. Set the two equal:
(x^33x^23x8)/(3x^24x6) = x/3
It appears they do not intersect. Typo?
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