precalc!!!!!
posted by L.Bianchessi .
The point (5,2) lies on the graph of y=f(x), and assume f^1(x) exists. Find the corresponding point on eAch graph.
A). Y=f^1(x)
I get (5,2)
B). Y=f^1(x)+4
I get (5,2)
C). Y=f^1(x+2)+3
I get (7,5)
Did I get these right?

say y = x  7
(5,2) lies on that graph
for f^1
x = y  7
y = x + 7
if x = 5 then y = 12
so I get
(5,12) 
say y = x  7
(5,2) lies on that graph
for f^1
x = y + 7
y = x  7
if x = 5 then y = 2
so I get
(5,2) 
B. My f^1(x) = x7
Y=f^1(x)+4
Y = (57) + 4
Y = 12+ 4 = 8
(5,8)
C.Y=f^1(x+2)+3
x+2 = 7
f^1(7) = 77 = 0
Y = 0 + 3 = 3