# precalc!!!!!

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The point (5,-2) lies on the graph of y=f(x), and assume f^-1(x) exists. Find the corresponding point on eAch graph.

A). Y=f^-1(x)

I get (-5,2)

B). Y=-f^-1(-x)+4
I get (5,2)

C). Y=f^-1(x+2)+3

I get (-7,5)

Did I get these right?

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