College Physics

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A proton moves with a velocity of vector v = (6ihat - 1jhat + khat) m/s in a region in which the magnetic field is vector B = (ihat + 2jhat - 3khat) T. What is the magnitude of the magnetic force this charge experiences?

answer in Newtons.

I tried F=qvb but the vectors are just stumping me. Any help is welcome!

  • College Physics -

    Compute the determinant:
    |i j k|
    |6 -1 1|
    |1 2 -3|
    Then calculate the magnitude of the resulting vector. Then multiply that by e.

    Why do you have an unnecessary 1 in front of the velocity j component? Is that a typing error?

    For the determinant, I get
    (4-2)i + (1+19)k + (12+1)k
    = 2i +20j +12k

    The force would be 1.6*10^-19*23.4 N

  • College Physics -

    I am still not understanding it the way you explained it but your answer was correct.

  • College Physics -

    You need to learn the method of taking the cross product of two vectors with determinants. That is what I did.

    For a brief summary see
    http://www.ucl.ac.uk/mathematics/geomath/level2/mat/mat121.html

  • College Physics -

    For the determinant, I get
    (4-2)i + (1+19)j + (12+1)k
    (a typo error was corrected)
    = 2i +20j +12k

    The magnitude of that vector is
    sqrt[2^2 + 20^2 + 12^2] = sqrt548 = 23.4

    The force would be 1.6*10^-19*23.4 N
    = 3.74*10^-18 N

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