1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s)

[N2O] = 0.383 M

I know I posted a similar question but I am having trouble with this one as well. Should I do 1/1.75 first and then add 1.10e-3 and then multiply by 1852?

Math(Thank you for your help) - john, Friday, March 9, 2012 at 8:51pm
P.E.M.D.A.S

Math(Thank you for your help) - Hannah, Friday, March 9, 2012 at 11:51pm
So first I did multiplication (1.10e-3)(1852) and then divided 1/1.75 and then added and I cant get the answer.

To solve the equation 1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s), you need to follow the correct order of operations (P.E.M.D.A.S).

1. Start by evaluating (1.10E-3)(1852) to find the value of this multiplication. This gives you 0.2032.

2. Next, divide 1 by 1.75 to find the value of 1/1.75. This gives you approximately 0.5714.

3. Now, add the result of step 1 (0.2032) to the result of step 2 (0.5714). This gives you approximately 0.7746.

4. Finally, take the reciprocal of the result obtained in step 3 to find [N2O]. The reciprocal of 0.7746 is approximately 1.292 M.

Therefore, the value of [N2O] is approximately 1.292 M.

Make sure to use parentheses when necessary to avoid confusion in complex equations.