physics
posted by Nick
You throw a 134 g ball straight up to a height of 43.0 m.
(a) Assume that the displacement of your hand is 0.70 m as you throw the ball straight up. How long is the ball is in your hand?
(b) Calculate the average force exerted by your hand while you are throwing it.

drwls
(a) release velocity = sqrt(2gH) = 29.0 m/s
Time in hand = 0.70 m/(Avg. Velocity) = 0.70/(29.0/2) = 0.048 s
(b) Force * Distance = Work = Potential Energy Gain at max. height
F*0.70 = M*g*H = 0.134*9.8*43 J
Solve for F in Newtons
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