Chemistry

posted by .

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has a partial pressure of 217.0 torr, 13.2 torr, and 13.2 torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 torr. The appropriate chemical equation is PCl3(g) + Cl2(g) <=> PCl5(g)
Calculate the new partial pressures of PCl3, Cl2, and PCl5

Am i supposed to find Kp first..? please help me!

  • Chemistry -

    Yes, I would find Kp first.

  • Chemistry -

    Hi lol

    Is this correct?:
    Kp = PPCl5/(PPCl3)(PCl2) = 217.0 torr/(13.2 torr)(13.2 torr) = 1.245

    x/(263 torr - x) = 1.245
    x = 327.435 - 1.245x
    2.245x = 327.435
    x = 145.85 torr = PPCl5

    263.0 total torr - 145.85 PCl5 torr = 117.15 torr - 13.2 torr = 103.95 torr for Cl2
    13.2 torr for Cl3?

  • Chemistry -

    I would do this. First I would convert torr to atm.
    PPCl5 = 217/760 = 0.2855 atm
    PPCl3 = 13.2/760 = 0.01737 atm.
    PCl2 = 13.2/760 = 0.01737 atm
    Total P = 243.4/760 = 0.3203 atm
    Cl2 added = 263-243 = 19.6 and 19.6/760 = 0.02579

    ............PCl3 + Cl2 ==> PCl5
    initial..0.01737.0.01737..0.2855
    add.............0.02579..........
    change.......-p....-p.......+2p
    equil.0.01737-p.0.04316-p..0.2855+2p
    Substitute into Kp expression with these ICE chart values and solve for p.

  • Chemistry -

    Hi Dr. Bob. I'm coming up with outrageous numbers for when I try to use atm's with my Kp value.. please look!

    Kp = PPCl5/PPCl3PCl2 = (0.2855)/(0.01737)(0.01737) = 946.3

    PCl3 : 0.01737-946.3 = -946.28 atm?!
    Cl2 : 0.04316 - 946.3 = -946.26 atm o.o
    PCl5 : 0.2855 + 2(946.3) = 1,892.8855 >.<

    when i tried it with torr it gave me 11.955, 31.555, and 219.49 >.< am i reading your directions correctly?

  • Chemistry -

    ohh i'm sorry i understand now thank you Dr. Bob!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chem

    A 12.3 vessel was found to contain N2, Ar He, and He. The total pressure in the vessel was 987 torr and the partial pressures of nitrogen, argon, and helium were 44 torr, 486 torr, and 218 torr, respectively. What was the pressure …
  2. chemistry urgent

    a mixture of NO, CO2, and O2 gases has a total pressure of 2.5x10^3 torr. if the partial pressure of NO is 800 torr and CO2 is 600 torr, what is the partial pressure of O2?
  3. chemistry

    A gas mixture, has a total pressure of 300. Torr and consists of equal masses of Ne and Ar. What is the partial pressure of Ar, in Torr?
  4. CHEMISTRY

    Equilibrium Equation with Partial Pressures PCl3(g) +Cl2(g) <-> PCl5(g)?
  5. ccbc

    A 12.3 vessel was found to contain N2, Ar He, and He. The total pressure in the vessel was 987 torr and the partial pressures of nitrogen, argon, and helium were 44 torr, 486 torr, and 218 torr, respectively. What was the pressure …
  6. chemistry

    at an equilibrium mixture of PCl5, PCl3, and Cl2 has partial pressures of 217.0 Torr, 13.2 Torr and 13.2 Torr respectively. a quantity of Cl2 is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of …
  7. chemistry

    at an equilibrium mixture of PCl5, PCl3, and Cl2 has partial pressures of 217.0 Torr, 13.2 Torr and 13.2 Torr respectively. a quantity of Cl2 is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of …
  8. chemistry

    A mixture of gases has the following partial pressure for the component gases at 20 degrees Celsius: oxygen 180.0 torr, nitrogen 3200 torr, and hydrogen 246.0 torr. Calculate the pressure of the mixture.
  9. chemistry

    The pressure of a mixture of H2 & N2 in container in 1200 torr.The partial pressure of N2 in the mixture is 300 torr.What is the ratio of H2 and N2 molecules in the mixture torr?
  10. Chemistry

    A gas mixture consists of equal masses of methane (molecular weight 16.0) and argon (atomic weight 40.0). If the partial pressure of argon is 200. torr, what is the pressure of methane, in torr?

More Similar Questions