Chemistry

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Calculate the [H+], [OH ‾ ], and the pH of 0.16 M solutions of:
hydroxylamine (HONH2, Kb = 1.1 10-8)

  • Chemistry -

    HONH2 I'll call RNH2
    ..........RNH2 + HOH ==> RNH3^+ + OH^-
    initial...0.16M............0.......0
    change......-x..............x......x
    equil.....0.16-x............x......x

    Kb = (RNH2)(OH^-)/RNH2
    Substitute from the ICE chart above and solve for x which = OH^-, then convert to H^+ and pH.

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