posted by Vickie
The position of a particle in meters is given by x =3.6t2 - 2.4t3 , where t is time in seconds.
A) Find the two times when the velocity is zero.
B) Calculate the position for each of those times.
V = dx/dt = 7.2 t - 7.2 t^2
A) V = 0 when t = 0 and t = 1 s
B) Susbtitute those times in the x(t) equation.