math
posted by Miep .
Robert has two watches, one which loses 6 seconds every 24 hours and one which gains 1 second
per hour. He sets both of them to the correct time at 6 : 00 p.m. How many hours will pass
before the positive diﬀerence between the time shown on both watches is 4 hours?

i hit my head on this question for a long time ! finally got the answer. total difference : 6seconds+24seconds  30seconds they lose in a day. now calculate the total seconds in four hours . which is 14400. now divide 14400 by 30 seconds. which will be 480. now multiple that number by 24 hours. the final and correct sanswer will be 11520. :)