math
posted by Emerson .
To get 8, what operations (+  x / sqrt) do I use between a series of four 3s (3_3_3_3=8)?

3x3  3/3
Respond to this Question
Similar Questions

Math(Roots)
sqrt(24) *I don't really get this stuff.Can somebody please help me? 
Math
How do you find a square root of a number that's not a perfect square? 
algebra,math,help
Use Property 2 to simplify each of the following radical expressions. sqrt (10)/ sqrt(49) My answer: sqrt (10) / (7) THis next one i need help: Use the properties for radicals to simplify each of the following expressions. Assume that … 
Math Help please!!
Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine … 
Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 … 
Algebra 2
Operations with Complex Numbers Simplify. 1. sqrt(144) 2. sqrt(64x^4) 3. sqrt(13)*sqrt(26) 4. (2i)(6i)(4i) 5. i13 6. i38 7. (5 – 2i) + (4 + 4i) 8. (3 – 4i) – (1 – 4i) 9. (3 + 4i)(3 – 4i) 10. (6 – 2i)(1 + i) 11. (4i)/(3+i) … 
Advanced Math
Can someone check these for me? Please? Use halfangle identity to find the exact value of cos165 degrees. (1/2) sqrt(2+sqrt(3)) Write the equation 2x+3y5=0 in normal form. (2sqrt(13)/13)x (3sqrt(13)/13)y+ (5 sqrt (13)/13) = 0 
Pre Cal.
Find three geometric means betwee sqrt(2) and 4sqrt(2). A: 2, 2sqrt(2), 4 Is 6 sqrt(2)+ 6 + 3sqrt(2)+... a convergent series? 
Math
Use a table of values of f(x) to estimate the value of the limit to four decimal places. lim_(x>infinity)(sqrt(2 x^2 + 4 x + 1)  sqrt(2 x^2 + 2 x + 7)) 1 
Calculus 3
I need help writing the series 4 + 1/5 + .3 + 1/(3 + sqrt 2) + 1/(9+ sqrt 3) + 1/(27 + sqrt 4) + 1/(81 + sqrt 5 .... I have played with using irrational numbers, natural log and a vast variety of exponential arrangements. Any help …