What is the reaction enthalpy for CaCO3(s) --> CaO(s) + CO2(g)?
should i be using a enthalpy reaction table?
Yes. Use the delta Ho formation tables.
dHrxn = (n*dH products) - (n*dH reactants)
perfect, i got a positive 178.3 kj/mol, which makes since because CaCO3 releases a lot of energy when it breaks apart, so there was more energy released when breaking apart then needed to originally form CaCO3
Thank you
Is that good? A +178.3 kJ for dHo means it is an endothermic reaction
Yes, using an enthalpy reaction table would be helpful in determining the reaction enthalpy for the given reaction. An enthalpy reaction table, also known as a standard enthalpy of formation table, provides the standard enthalpy change (∆H°) values for various chemical reactions at standard conditions (usually 298 K and 1 atm).
To calculate the reaction enthalpy for the reaction CaCO3(s) → CaO(s) + CO2(g), you need to find the standard enthalpy change values (∆H°f) for each of the compounds involved.
1. Look up the standard enthalpy of formation value for CaCO3(s) in the enthalpy reaction table. It is usually given in kilojoules per mole (kJ/mol).
2. Look up the standard enthalpy of formation value for CaO(s) in the enthalpy reaction table.
3. Look up the standard enthalpy of formation value for CO2(g) in the enthalpy reaction table.
4. The reaction enthalpy (∆H°) is the sum of the products minus the sum of the reactants:
∆H° = (∆H°f of products) - (∆H°f of reactants)
By subtracting the sum of the reactants' standard enthalpy of formation values from the sum of the products' standard enthalpy of formation values, you can calculate the reaction enthalpy for the given reaction.