Multiply ( x-1) (2x(2)-xt5)<- the( 2 )is an exponent
Is the 5 an exponent?
No 2 is but i had to put it in parenthesis
3cm it's mass4000 find its mass 4000g
To multiply the expression (x-1) and (2x^2-xt^5), you can use the distributive property.
The distributive property states that for any numbers a, b, and c:
(a + b)c = ac + bc
Applying the distributive property to our expression, we can multiply each term of the first expression, (x-1), by each term of the second expression, (2x^2-xt^5).
(x-1)(2x^2-xt^5) = x(2x^2-xt^5) - 1(2x^2-xt^5)
Now, simplify each term:
x(2x^2) - x(xt^5) - 1(2x^2) + 1(xt^5)
2x^3 - x^2t^5 - 2x^2 + xt^5
Combining like terms,
2x^3 - 2x^2 - x^2t^5 + xt^5
So, the multiplication of (x-1) and (2x^2-xt^5) is 2x^3 - 2x^2 - x^2t^5 + xt^5.