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Given that the equation of the circle is x^2 + y^2 +2x -8y+5 =0
(i)Find the centre and radius of the circle
(ii)Determine whether the line x-3y=8 is tangent to the given circle

  • maths -

    1. x^2+2x+(2/2)^2+Y^2-8y+(-8/2)^2=-5+1+16.
    X^2+2x+1 + Y^2-8y+16 = 12.
    (x+1)^2 + (y-4)^2 = 12.
    (x-h)^2 + (y-k)^2 = r^2.

    C(h,k).
    C(-1,4).

    r^2 = 12.
    r = 2*sqrt3 = 3.46.

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