# calculus

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1. If 3x^2+2xy+y2=2 then the value of dy/dx x = 1 is
A. -2 B. 0 C. 2 D. 4 E. not defined

• calculus -

3x^2+2xy+y2=2
6x + 2y + 2xy' + 2yy' = 0

x=1 ==> y=-1

6(1) + 2(-1) + 2(1)y' + 2(-1)y' = 0
6 - 2 + 2y' - 2y' = 0
4 = 0

(e) undefined

The graph is an ellipse. At (1,-1) there is a vertical tangent

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