posted by Anonymous .
How many grams of PI3 could actually be produced from 250 g of I2 and excess phosphorous if the reaction gives a 98.5% yield?
P4 + 6I2 --> 4PI3
How many mols I2 do you have? mols = g/molar mass
4 moles I2 produce 6 mols PI3.
How many grams is that? g = moles x molar mass That give you the theoretical yield. Convert to actual yield by theoretical yield x 0.985 = actual yield.
By the way, you misspelled phosphorus.