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a body of mass 5 kg is thrown vertically upwards with a speed of 10m/s what is its k.e. when it is thrown find its potential energy when it reaches at highest poiint also find maximum height attained by the body?

  • Science -

    a. KE = 0.5m*Vo = 2.5*(10)^2 = 250 Joules

    b. hmax = (Vf^2-Vo^2)/2g.
    hmax = (0-(10)^2 / -19.6 = 5.10 m.

    c. PE = mg*h = 5 * 9.8 * 5.1=250 Joules

  • Science -

    m=5kg
    V=10m/s
    K.E=1/2mv^2
    P.E=mgh
    K.E=P.E
    K.E=1/2mv^2
    =1/2x10x5x5
    =125
    P.E=125
    Mgh =P.E
    5x10xh=125
    10h=125/5=25
    h=25/10=2.5 answer

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