How many grams of carbon dioxide are produced in C3H8+5O2 -> 3CO2+4H2O
Oh, it's party time! Let's calculate the number of grams of carbon dioxide produced in the combustion of propane. The molar mass of C3H8 is 44 grams/mol, and each molecule of C3H8 produces 3 molecules of CO2. So, if you start with 1 mole of C3H8, you'll also produce 3 moles of CO2.
Now, to convert moles to grams, we can use the molar mass of CO2, which is 44 grams/mol. Since we have 3 moles of CO2, we multiply it by the molar mass:
3 moles CO2 x 44 grams/mol = 132 grams of CO2
So, in the combustion of C3H8, you'll get approximately 132 grams of CO2. And that's enough carbon dioxide to make the atmosphere gasp! *wink*
To calculate the number of grams of carbon dioxide (CO2) produced in the reaction C3H8 + 5O2 -> 3CO2 + 4H2O, you'll need to follow these steps:
Step 1: Determine the molar mass of C3H8 (propane).
The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of hydrogen (H) is 1.01 g/mol. Multiply the molar mass of carbon by 3 and the molar mass of hydrogen by 8, then add them together:
(3 * 12.01 g/mol) + (8 * 1.01 g/mol) = 44.11 g/mol
Step 2: Calculate the molar mass of CO2 (carbon dioxide).
The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. Multiply the molar mass of carbon by 1 and the molar mass of oxygen by 2, then add them together:
(1 * 12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol
Step 3: Calculate the number of moles of C3H8 involved.
To balance the equation, 1 mole of C3H8 reacts to form 3 moles of CO2. Therefore, for every mole of C3H8, 3/1 = 3 moles of CO2 are produced.
Step 4: Compute the number of moles of CO2 produced.
Since the reaction produces 3 moles of CO2 for every mole of C3H8, you can calculate the number of moles of CO2 by multiplying the molar mass of C3H8 by the number of moles of C3H8:
44.11 g/mol * (3 moles CO2 / 1 mole C3H8) = 132.33 g CO2
So, approximately 132.33 grams of carbon dioxide (CO2) are produced in the reaction.
To determine the number of grams of carbon dioxide produced in the reaction C3H8 + 5O2 -> 3CO2 + 4H2O, we need to use the concept of stoichiometry.
First, we need to find the balanced equation for the reaction, which is already given:
C3H8 + 5O2 -> 3CO2 + 4H2O
From the balanced equation, we can see that for every 3 moles of CO2 produced, 1 mole of C3H8 is consumed. Therefore, the ratio of moles of CO2 to moles of C3H8 is 3:1.
Next, we need to know the molar mass of CO2, which is calculated by adding together the atomic masses of carbon (C) and oxygen (O). The atomic mass of carbon is approximately 12 grams per mole, and the atomic mass of oxygen is about 16 grams per mole. Therefore, the molar mass of CO2 is:
Molar mass of CO2 = 12 g/mol (for carbon) + 2 * 16 g/mol (for oxygen) = 44 g/mol
Now, we can calculate the number of moles of CO2 produced using the given information that 1 mole of C3H8 produces 3 moles of CO2:
Moles of CO2 = Moles of C3H8 * (3 moles of CO2 / 1 mole of C3H8)
Finally, we can convert the moles of CO2 to grams using the molar mass of CO2:
Grams of CO2 = Moles of CO2 * Molar mass of CO2
Please provide the mass of C3H8 in grams, and we can calculate the mass of CO2 produced.