Calculus
posted by Johnathan .
find f'(x) if f(x)=x^2*e^x*(3x1)^3

f(x) = (x^2) (e^x) (3x1)^3
if y = uvw
then y' = u'(vw) + v'(uw) + w'(uv)
I see 3 factors in f(x) to match that pattern.
Does not look difficult, just carefully follow the above.
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