math
posted by upasna .
construct an equilateral triangle ABC in which altitude drawn from opposite vertex is 3.5 cm.Also construct a triangle APR similar to a triangle such that each side of the triangle APR is 1.5 times that of the corresponding side of triangle ABC.

tanA = h/(b/2).
tanA = 3.5 / (b/2).
tan60 = 3.5 / (b/2).
(b/2)tan60 = 3.5.
b/2 = 3.5 / tan60. = 2.02.
b = 4.04 cm.
a = b = c = 4.04 cm.
A = B = C = 60 Deg.