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construct an equilateral triangle ABC in which altitude drawn from opposite vertex is 3.5 cm.Also construct a triangle APR similar to a triangle such that each side of the triangle APR is 1.5 times that of the corresponding side of triangle ABC.

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    tanA = h/(b/2).
    tanA = 3.5 / (b/2).
    tan60 = 3.5 / (b/2).
    (b/2)tan60 = 3.5.
    b/2 = 3.5 / tan60. = 2.02.
    b = 4.04 cm.

    a = b = c = 4.04 cm.

    A = B = C = 60 Deg.

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