Tanya had $1.19 in coins. None of the coins were dollars or 50-cent pieces. Josie asked Tanya for change for a dollar, but she did not have the correct change. Which coins did Tanya have

3 quarters, 4 dimes and 4 pennies.

.75+.40+.04=1.19

To determine which coins Tanya had, let's break down the problem step by step:

1. We know that Tanya had $1.19 in coins and that none of the coins were dollars or 50-cent pieces.

2. Let's assume Tanya only had coins in denominations smaller than 50 cents.

3. We also know that Josie asked Tanya for change for a dollar and that Tanya did not have the correct change.

4. If Tanya had only 25-cent pieces, she would need five of them to make a dollar. However, this would leave her with only 19 cents remaining, which cannot be made up using only smaller coins.

5. If Tanya had only 10-cent pieces, she would need ten of them to make a dollar. This would leave her with only nine cents remaining, which also cannot be made up using only smaller coins.

6. If Tanya had only 5-cent pieces, she would need twenty of them to make a dollar. This would leave her with only nineteen cents remaining, which fits with the given amount.

Therefore, Tanya had nineteen 5-cent pieces (nickels).

So, Tanya had 19 nickels.

To find out which coins Tanya had, we can try a process of elimination.

Let's start by assuming Tanya had one of each coin: a penny, a nickel, a dime, and a quarter.

The total value of these coins would be 1 cent (penny) + 5 cents (nickel) + 10 cents (dime) + 25 cents (quarter) = 41 cents. However, this total is less than the given amount of $1.19.

So, we need to adjust our assumption by removing one of the coins and trying again.

If we remove the penny, the new total would be 5 cents (nickel) + 10 cents (dime) + 25 cents (quarter) = 40 cents.

This is still less than $1.19, so let's remove another coin.

If we remove the nickel, the new total would be 10 cents (dime) + 25 cents (quarter) = 35 cents.

Again, still less than $1.19, so let's remove the next coin.

If we remove the dime, the new total would be 25 cents (quarter) = 25 cents.

This is still less than $1.19, so let's remove the last coin.

If we remove the quarter, the new total would be 0 cents.

Since this is less than the given amount of $1.19, we can conclude that Tanya did not have one of each coin.

Now, considering the remaining possibilities, Tanya must have had a dime, a nickel, and some pennies.

Let's calculate the remaining amount by finding the difference between $1.19 and the value of a dime and a nickel:
$1.19 - 10 cents (dime) - 5 cents (nickel) = $1.19 - 15 cents = $1.04.

Since none of the remaining coins can be dollars or 50-cent pieces, the only possible coins Tanya had are pennies.

To see how many pennies Tanya had, divide the remaining amount, $1.04, by the value of a penny:

$1.04 รท 1 cent (penny) = 104 pennies.

Therefore, Tanya had a dime, a nickel, and 104 pennies.